[PHP-DB] Problem with php and mysql From: Emmanuel Halphen (manu <email protected>)
Date: 09/30/00

Hi,

I have a little problem with php and MySQL.

This is an extract of the code of my page :

$test = "SELECT * FROM Test WHERE $Toto <> 1";
$rtest = mysql_db_query("test",$test)
while($etest = mysql_fetch_array($rtest)) {
echo $etest["Numero"];
}

While I execute this page, I have the following error :

Warning: Supplied argument is not a valid MySQL result resource

When I put in the code : echo $rtest; , I have the following response :
Resource id #2

Does somebody has an answer or an explication ?

Thanks a lot.

Emmanuel 

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