Re: [PHP-DB] Problem posting variables From: Adv. Systems Design (asd_2000 <email protected>)
Date: 11/15/00

try something like this...notice the = sign!

<input type="hidden" name="overview"
value="<?=$frm["overview"]?>">

Luis

--- Olivier Bourgeois <olivier <email protected>> wrote:
> > I am trying to create a form to enter orders for
> eBay auctions into a mySQL database. The first
> step, here:
> >
> > http://www.wholesalemegastore.com/ebay/step1.php3
> >
> > looks up the auction in a table, and displays our
> part number as well as the description in step two
> using
> >
> > printf("%s\n", $myrow["variable_name"]);
> >
> > I wish to post these to step3.php3 using
> >
> > <input type=hidden name="variable_name" value="<?
> echo $variable_name ?>">
> >
> > in step two, and to display these variables in
> step three using
> >
> > echo "$variable_name\n";
> >
> > but the values don't seem to show up. Everything
> else shows up but these two variables. Any
> suggestions? If you want to try it you can use
> auction 491469283. I haven't coded for Continue
> button so you would need to press "Finished" in step
> two.
> >
>
> Hello,
> I've watched the thing : first there's a parse
> error in your script on line 266, but is not the
> cause of the problem. You should double check the
> end form tag </form> because it stands just 12 lines
> under the begining, also you hidden input aren't
> in the form. So it's the reason why the data aren't
> posted. Or the other possibility is that you have
> two forms in your document, but the second form
> isn't closed due to the parse error. BTW I find it
> more clear to have just one form for all the data.
>
> bye
>
>
> > --
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