[PHP-DEV] Bug #289 Updated: PHP does not evaluate the () (Function call) operator correctly From: Bug Database (php-dev <email protected>)
Date: 04/24/98

ID: 289
Updated by: zeev
Reported By: kk <email protected>
Status: Closed
Bug Type: Performance problem
Assigned To:
Comments:

This syntax is not supported. Only strings
and variables can be used as function names (not any
other expressions)

You can use
$foo = $x.$y;
$foo()

Full Bug description available at: http://ca.php.net/bugs.php3?id=289