Re: [PHP-DEV] 3.0.12: mysql_store_result in php3_mysql_query From: Rasmus Lerdorf (rasmus <email protected>)
Date: 09/02/99

Hrm.. That does look a bit odd. This change was made Friday, October 24,
1997 by Zeev. I am sure he remembers why he made the change! ;)

See http://cvs.php.net/cvsweb.cgi/functions/mysql.c and go down to the
1.41 change. Zeev's comment just says,
"Fixed a free() that should have been efree() on a failed mysql_connect()"
which doesn't really seem to relate to this particular change.

On Thu, 2 Sep 1999, David Sklar wrote:

>
> I have a page that does:
>
> $r = mysql_query('select ping from ping');
> if ($r) {
> if ($ob = mysql_fetch_object($r)) {
> echo $ob->ping."\n";
> } else {
> echo "Can't get ob\n";
> }
> } else {
> echo "Can't do query\n";
> }
>
> Very infrequently, when accessing this page, I get a "PHP 3 Warning: 1 is not
> a MySQL result index" at the line with mysql_fetch_object(). So mysql_query is
> returning 1 (or TRUE that gets evaluated to 1?) but it's still not really a
> result handle.
>
> Could the following code in php3_mysql_query() be responsible: ?
>
> if ((mysql_result=mysql_store_result(mysql))==NULL) {
> /*php3_error(E_WARNING,"Unable to save MySQL query result");
> RETURN_FALSE;
> */
> RETURN_TRUE;
> }
>
>
> Why is it returning true if there was an error? mysql_store_result() returns
> NULL if an error occurs.
>
>
> -dave
>
>
>
>
> 

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