[PHP-DEV] PHP 4.0 Bug #8115 Updated: variable passed by reference incorrectly handled From: stas <email protected>
Date: 12/05/00

ID: 8115
Updated by: stas
Reported By: christian <email protected>
Status: Closed
Bug Type: Scripting Engine problem
Assigned To:
Comments:

This is exactly as it is meant to work. Please read
"References explained" in the manual. When you do the unset,
you effectively destroy local variable $a, breaking the
reference. Now when you mention $a again, it's not
referenced to $my_var anymore - it's a new variable.

Previous Comments:
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[2000-12-05 06:27:46] christian <email protected>
It concerns variables passed by reference... and the unset() function.

# Let's define a very simple function that converts an array to a string :
function foo(&$a)
{
   $an_array = array("abcdef");
   unset($a);
   
   for ($i=0; $i<sizeof($an_array); $i++)
        $a = $a . $an_array[$i];
}

# and call it :
foo($my_var);

# $my_var is NOT EQUAL TO "abcdef" !!!!!

However it works fine when we don't try to unset the $a variable. (replacing the line with $a = "").

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Full Bug description available at: http://bugs.php.net/?id=8115 

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