[PHP-DEV] PHP 4.0 Bug #8139 Updated: NULL and isset From: joey <email protected>
Date: 12/06/00

ID: 8139
Updated by: joey
Reported By: richard.heyes <email protected>
Status: Feedback
Bug Type: Scripting Engine problem
Assigned To:
Comments:

The question is: should passing an unset variable by reference
generate a warning?

Previous Comments:
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[2000-12-06 12:57:39] richard.heyes <email protected>
<?php
function foo(&$bar){
    return TRUE;
}

foo($bar);

print($bar);

if(!isset($bar))
    print('Bar is not set!');
?>

With notices turned on (error_reporting) the call to print($bar) does not throw an error. However the bit below it runs the print() call. So if it's not set, the first print should throw an error regarding the unset $bar. Seems very contradictory. FWIW the type of $bar after the call to foo() is NULL.

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Full Bug description available at: http://bugs.php.net/?id=8139 

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