[PHP-DEV] PHP 4.0 Bug #8472 Updated: calling a function in a regular expression From: simon.southwood <email protected>
Date: 12/29/00

ID: 8472
User Update by: simon.southwood <email protected>
Status: Open
Bug Type: *Regular Expressions
Description: calling a function in a regular expression

oops
$html=$html="<%image1%>some junk in here<%image2%>even more junk in
here<%image3%>and some more for good measure<%image4%>";

Previous Comments:
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[2000-12-29 04:53:38] simon.southwood <email protected>
function image($arrayRef)
{
$arrayRef += 5;
return $arrayRef;
}
$html="<%image1%>some junk in here<%image2%>even more junk in here<%image3%>and some more for good measure<%image4%>
print(image("34"));
$pat="%image([0-9])%";
$rep="fdg".image("\1");
$html=ereg_replace($pat, $rep, $html);

/*
the function works fine if "$arrayRef += 5;" is commented out (it returns exactly whatever "\1" is.
it also works fine when called with either a string or an integer as argument, called outside the regexp function.

however, inside the regexp it always returns 5.

i dunno if this is a bug, if not then i do apologise, and i'll find another way of doing this.
*/

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Full Bug description available at: http://bugs.php.net/?id=8472 

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