[PHP-DEV] PHP 4.0 Bug #10389 Updated: mysql_query(); returns an invalid result resource From: pmarks <email protected>
Date: 04/19/01

ID: 10389
User Update by: pmarks <email protected>
Old-Status: Feedback
Status: Open
Bug Type: MySQL related
Description: mysql_query(); returns an invalid result resource

I checked what you said with mysqladmin and mysql. The
database "ue" does exist, as does the table "jobsc." Thanks
for saying something about the table being empty, as it was.
I fixed this problem (I'd had it before, but i just did this new
script by itself to make sure) and added 1 entry to the table "jobsc." PHP4 still returns the same warning as before on the
"SELECT * FROM jobsc" and in the mysql console, executing
that instruction returns the one and only row in the table jobsc.

Previous Comments:
---------------------------------------------------------------------------

[2001-04-18 20:29:19] cnewbill <email protected>
My bad...it would not return false. It's been a long long day.

But it would return false if the table jobsc did not exist or the database ue did not exist.

-Chris

---------------------------------------------------------------------------

[2001-04-18 20:26:15] cnewbill <email protected>
Your query is not returning any rows, and as such mysql_query returns false. False of course is not a valid mysql result and thus the "Warning".

If you are 100% certain the query returns results then that would be a problem, otherwise this is not a bug.

Please check this query from the mysql command line and reopen if there really is a problem.

-Chris

---------------------------------------------------------------------------

[2001-04-18 19:45:58] pmarks <email protected>
Here is the code I am using that produces the error:

<?php
    $db = mysql_connect("localhost");
    mysql_select_db("ue", $db);
    $result = mysql_query("SELECT * FROM jobsc");
    $rows = mysql_num_rows($result);
?>

on the last line is where the error is generated. In
any browser, I see:

Warning: Supplied argument is not a valid MySQL result
resource ...

My setup contains apache 1.3.19 with the static PHP 4.0.4pl1
module compiled in. My configure lines for PHP are:

./configure --with-apache=/home/apache_1.3.19
--with-mysql=/usr/local/mysql

/usr/local/mysql is the install directory for mysql

That is all the information I believe I have, and I'm
relatively sure that PHP is not crashing, per say.

---------------------------------------------------------------------------

Full Bug description available at: http://bugs.php.net/?id=10389

-- 
PHP Development Mailing List <http://www.php.net/>
To unsubscribe, e-mail: php-dev-unsubscribe <email protected>
For additional commands, e-mail: php-dev-help <email protected>
To contact the list administrators, e-mail: php-list-admin <email protected>