[PHP-DEV] Bug #10887 Updated: Variables from forms being undefined From: mikepeterson <email protected>
Date: 05/15/01

ID: 10887
User Update by: mikepeterson <email protected>
Old-Status: Feedback
Status: Open
Bug Type: Unknown/Other Function
Operating system: Windows 2000 Pro
PHP Version: 4.0.5
Description: Variables from forms being undefined

This function did not work in PHP4.05:
elseif ($delete) {

        // delete a record

    $sql = "DELETE FROM models WHERE model_id=$model_id";

    $result = mysql_query($sql);

    echo "$sql Record deleted!<p>";
}

Unless I added isset() like so:

elseif (isset($delete)) {}

But as I added that in other functions that returned a value from mySQL, every value returned would be "1" or TRUE.

Previous Comments:
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[2001-05-15 16:23:28] derick <email protected>
This script shows no isset(), please be a little more descriptive.

Derick

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[2001-05-15 16:01:31] mikepeterson <email protected>
Here is an example of a script that returned the error in 4.05, and works in 4.04.

elseif ($delete) {

        // delete a record

    $sql = "DELETE FROM models WHERE model_id=$model_id";

    $result = mysql_query($sql);

    echo "$sql Record deleted!<p>";

---------------------------------------------------------------------------

[2001-05-15 15:54:10] derick <email protected>
Please post a short reproducing script. (short is under 10 lines)

---------------------------------------------------------------------------

[2001-05-15 15:50:01] mikepeterson <email protected>
When using PHP4.05 my script always told me a variable from a form I had on the page was undefined. Using isset() the script ran without problems, but returned every query with "1" (my best guess is that is TRUE from isset()). I installed PHO4.04 and everything ran perfectly.

Mike Peterson

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Full Bug description available at: http://bugs.php.net/?id=10887 

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