[PHP-DEV] Bug #11555 Updated: date() format addition From: derick <email protected>
Date: 06/20/01

ID: 11555
Updated by: derick
Reported By: martin <email protected>
Old-Status: Open
Status: Closed
Bug Type: Feature/Change Request
Operating system:
PHP Version: 4.0.5
Assigned To:
Comments:

You can use the strftime function already, it's the %W modifier.
But it would be useful if date would support it indeed.

Previous Comments:
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[2001-06-20 04:44:17] martin <email protected>
i live in sweden, where displaying weeknumbers in calendars of any sort is common. the
following code does the work, tho i'd be very happy if it could be supported to be returned
from the date() function.

switch(date("w",mktime(0,0,0,$mon,$daycnt+1,$year))) {
        case 1: $daysub=0; break;
        case 2: $daysub=1; break;
        case 3: $daysub=2; break;
        case 4: $daysub=3; break;
        case 5: $daysub=4; break;
        case 6: $daysub=5; break;
        case 0: $daysub=6; break;
}
$weeknumber=round((date("z", mktime(0,0,0, date("m"),date("d")+1-$daysub,date("Y")))+7)/7);
if($weeknumber==53) {
        //some years have 53 weeks & some 52
        //so we check next weeks weeknumber, if its 1 this is week 53, otherwise, this is week 1.
        switch(date("w",mktime(0,0,0,date("m"),date("d")+8,date("Y")))) {
                case 1: $daysub=0; break;
                case 2: $daysub=1; break;
                case 3: $daysub=2; break;
                case 4: $daysub=3; break;
                case 5: $daysub=4; break;
                case 6: $daysub=5; break;
                case 0: $daysub=6; break;
        }
        $tmpweeknumber=round( (date("z", mktime(0,0,0, date("m"), date("d")+8-$daysub, date("Y")))+7)/7);
        if($tmpweeknumber==1) $weeknumber=53;
        else $weeknumber=1;
}

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[2001-06-19 05:41:56] martin <email protected>
i live in sweden, where displaying weeknumbers in calendars of any sort is common. the following code does the work, tho i'd be very happy if it could be supported to be returned from the date() function.

the algorithm is (mondaynumber+7)/7
where mondaynumber is the day of the year of the monday of the current year

switch(date("w")) {
        case 1: $daysub=0; break;
        case 2: $daysub=1; break;
        case 3: $daysub=2; break;
        case 4: $daysub=3; break;
        case 5: $daysub=4; break;
        case 6: $daysub=5; break;
        case 0: $daysub=6; break;
}
$weeknumber=(date ("z", mktime(0,0,0, date("m"), date("d")-$daysub, date("Y")) )+7)/7;

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