[PHP-DEV] Bug #13315 Updated: problem with function definitions From: hholzgra <email protected>
Date: 09/15/01

ID: 13315
Updated by: hholzgra
Reported By: php <email protected>
Status: Bogus
Bug Type: *General Issues
Operating System: WIN98/APACHE1.3.19
PHP Version: 4.0.4pl1
New Comment:

no way, default values are evaluated at compile time
and there is no $foo set at all as the program didn't
start to run by that time

what you want to do is something like

  function showvar ( $bar = NULL ) {
    if ( $bar === NULL ) {
      $bar = $GLOBALS['foo'];
    }
    echo $bar;
  }

Previous Comments:
------------------------------------------------------------------------

[2001-09-15 05:43:00] php <email protected>

why is that? I really need this:(
Will a later version of php support constructions like this?

------------------------------------------------------------------------

[2001-09-15 05:28:13] mfischer <email protected>

Shouldn't. Default values must be constant expressions.

Not a bug, bogusified.

- Markus

------------------------------------------------------------------------

[2001-09-15 05:11:56] php <email protected>

<?php
    $foo = 'foo';
    function showvar( $bar = $foo )
    {
        //global $foo
        //doesn't work either
        echo $bar;
    }
    showvar();
    showvar('bar');
?>

gives me a parse error on line 3:(

also:

<?php
    $foo = 'foo';
    function returnvar()
    {
        global $foo;
        return $foo;
    }

    function whatisvar( $bar = returnvar() )
    {
        echo $bar;
    }
?>

gives me this:
Parse error: parse error, expecting `')'' in c:/path/to/script/test.php on line 9

Should work, shouldn't it?

------------------------------------------------------------------------

Edit this bug report at http://bugs.php.net/?id=13315&edit=1 

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