 |
 |
 |
 |
|
|
Date: 09/28/01
- Next message: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Previous message: Zeev Suraski: "Re: [PHP-DEV] why does exit() print its argument?"
- In reply to: Jason Greene: "Re: [PHP-DEV] why does exit() print its argument?"
- Next in thread: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Reply: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Reply: Boian Bonev: "Re: [PHP-DEV] why does exit() print its argument?"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
At 22:17 28-09-01, Jason Greene wrote:
>Why does exit still set the exit status then?
Ok, apparently it does (didn't recall that it does). I'm not sure what the
logic behind this is.
Zeev
-- PHP Development Mailing List <http://www.php.net/> To unsubscribe, e-mail: php-dev-unsubscribe <email protected> For additional commands, e-mail: php-dev-help <email protected> To contact the list administrators, e-mail: php-list-admin <email protected>
- Next message: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Previous message: Zeev Suraski: "Re: [PHP-DEV] why does exit() print its argument?"
- In reply to: Jason Greene: "Re: [PHP-DEV] why does exit() print its argument?"
- Next in thread: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Reply: Jim Winstead: "Re: [PHP-DEV] why does exit() print its argument?"
- Reply: Boian Bonev: "Re: [PHP-DEV] why does exit() print its argument?"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]