Re: [PHP-DEV] why does exit() print its argument? From: Yasuo Ohgaki (yasuo_ohgaki <email protected>)
Date: 09/30/01

Markus Fischer wrote:
>>Usualy I am very much against breaking backwards compatibility, but in this
>>case I think it's the best thing to do... Because:
>>- It's already documented that way
>>- It's the 'expected' behaviour (from other languages, and from the docs)
>>
>>As Rasmus said: It would be surprising if this broke a lot of (or even any)
>>code.
>>
>
> +1
>
> Hey, my second vote O_o

-1 for PHP 4.0.x
+1 for PHP 4.1 or greater. 

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