[PHP-DOC] #20743 [Asn->Csd]: mysql_error in mysql code examples From: pollita <email protected>
Date: 12/01/02

 ID: 20743
 Updated by: pollita <email protected>
 Reported By: renota <email protected>
-Status: Assigned
+Status: Closed
 Bug Type: Documentation problem
 Operating System: Linux
 PHP Version: 4.2.3
 Assigned To: pollita
 New Comment:

This bug has been fixed in CVS.

In case this was a PHP problem, snapshots of the sources are packaged
every three hours; this change will be in the next snapshot. You can
grab the snapshot at http://snaps.php.net/.
 
In case this was a documentation problem, the fix will show up soon at
http://www.php.net/manual/.

In case this was a PHP.net website problem, the change will show
up on the PHP.net site and on the mirror sites in short time.
 
Thank you for the report, and for helping us make PHP better.

Previous Comments:
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[2002-12-01 03:04:11] renota <email protected>

Hello,
I answer questions on a php help bbs (www.phpworld.com).
One of the most common problems reported is that the users
don't know why their database calls are not working.
Usually they have copied the code right out of the
examples (e.g. mysql_connect()), which do not utilize
mysql_error(). I was wondering if these examples could be
changed to use mysql_error() and thus reduce newbie
confusion.
Thank you for your time.

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