[PHP-DOC] #21288 [Com]: PHP does referencing when i want to create a *copy* of an array of objects From: stephan <email protected>
Date: 12/30/02

 ID: 21288
 Comment by: stephan <email protected>
 Reported By: empx <email protected>
 Status: Open
 Bug Type: Documentation problem
 Operating System: Windows XP SP1
 PHP Version: 4.3.0
 New Comment:

Just FYI, i've reproduced this (using the code from the
original poster) on PHP 4.2.0 under Linux.

Previous Comments:
------------------------------------------------------------------------

[2002-12-30 08:57:31] moriyoshi <email protected>

It seems more explanation should have been needed...

This problem is due to misleading behavior of array copies. PHP
scripting engine doesn't perform deep-copy on any elements of an array
while it copies *the container* of them indeed.

This will be fixed in ZendEngine2. Stay tuned.

------------------------------------------------------------------------

[2002-12-30 08:45:08] moriyoshi <email protected>

Verified. This is yet another "shallow copy" issue.

See http://bugs.php.net/20993

------------------------------------------------------------------------

[2002-12-30 06:52:59] empx <email protected>

Hello, i have some problems with understanding the following:

class Test {
var $a;
function Test() {
$this->a = 0;
}
function test2() {
}
}

$a[0] = new Test;
$b = $a;
$a[0]->a = 1;
echo($b[0]->a);

This outputs 0 as i would expect..but:

$a[0] = new Test;
$a[0]->test2();
$b = $a;
$a[0]->a = 1;
echo($b[0]->a);

This outputs 1, and i dont understand this, PHP seems to do some sort
of
referencing here, though i dont want any.. $b[0] = $a[0]; works and
creates
a real copy, but i was still wondering if $b = $a shouldnt create a
copy
aswell instead of this referencing stuff...

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