Re: [PHP] problem with image button From: Mark Maggelet (maggelet <email protected>)
Date: 09/30/00

On Sat, 30 Sep 2000 15:02:11 -0500 (CDT), Matt McClanahan
(cardinal <email protected>) wrote:
>On Sat, 30 Sep 2000, Mark Maggelet wrote:
>
>> Hi there,
>>
>> Let's say I have a form with three image buttons:
>> <input type=image name=add src="add.gif">
>> <input type=image name=delete src="delete.gif">
>> <input type=image name=update src="update.gif">
>>
>> when I process the form I want to see what button was pressed, but
>> instead of add being set, add.x and add.y get set.
>>
>> now the question is: what's the best way to check which one is set
>> since doing this:
>>
>> if(isset($add.x)) ...
>>
>> gives a parse error?
>
>Since $add.x is an invalid variable name, PHP has instead set
$add_x.
>
>Matt

thanks Matt,
that did it.

- Mark 

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