Re: [PHP] Creating Image... From: hugh danaher (hdanaher <email protected>)
Date: 07/31/02

You might also want to add a "quality" factor to the imagejpeg() function if
the image "as is" looks a bit ratty.
$factor="100" // or another suitable number between 100 and 0
imagejpeg($im, "test/im.jpg",$factor);
hope this helps.
Hugh

----- Original Message -----
From: "Andrew Chase" <andrew.chase <email protected>>
To: <php-general <email protected>>
Sent: Wednesday, July 31, 2002 1:10 PM
Subject: RE: [PHP] Creating Image...

> To write a GD image to disk as a jpeg, do this instead:
>
>
> $im = imagecreate(50,100);
>
> imagejpeg($im, "test/im.jpg");
>
>
> You don't need to use file handlers. Of course, without doing anything
like
> adding text or lines to $im, it will just be written to disk as a blank
> image. :)
>
> -Andy
>
> > -----Original Message-----
> > From: mp [mailto:lietuva <email protected>]
> > Sent: Wednesday, July 31, 2002 11:11 AM
> > To: php-general <email protected>
> > Subject: [PHP] Creating Image...
> >
> >
> > I want to create simple image...
> > I execute this script:
> >
> > $im = imagecreate (50, 100);
> > $fp = fopen("test/im.jpg","w");
> > fwrite($fp, imagegd($im));
> > fclose($fp);
> >
> > But there is some problems about this...
> > Could somebody help me?
> > Could somebody help me?
>
>
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