Date: 12/12/99
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Good afternoon,
I have a question regarding variable variables as object names:
The following code does not work:
$var = "cart_st";
$st_ID = $db->f("st_ID");
$var .= $st_ID;
//$$var is substituted by eg: $cart_st1
//echo $$var shows: Object
$$var->add_item($art,$num); //
It seams that in front of the -> operater, the $$ substitution does not
work. Can
somebody give me an alternative?
Martin
*****************************************
Martin Decker, martin.decker <email protected>
Telekommunikationstechnik und -systeme
Fachhochschule Salzburg
Jakob-Haringer-Str. 1a/II/12
Tel. 0664 5775697
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