Date: 07/15/00
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When $vaname is an array $append is not considered:
while(list($i, $h) = each($varname)) {
$str = $this->subst($h);
$this->set_var($target, $str);
}
Shouldn't it be instead?
What about this:
function parse($target, $varname, $append = false) {
if (!is_array($varname)) { $varname = array($varname); }
reset($varname);
while(list($i, $h) = each($varname)) {
$str = $this->subst($h);
if ($append) {
$this->set_var($target, $this->get_var($target) . $str);
} else {
$this->set_var($target, $str);
}
}
}
-- Luca - De Whiskey's - De Vitis aliases: Luca ^De [a-zA-Z]*i'?s$ Undergraduate Student of Computer Science at Bologna University. e-mail: devitis at (students\.)?cs\.unibo\.it home page: http://(caristudenti|www)(\.students)?\.cs\.unibo\.it/~devitis--------------------------------------------------------------------- To unsubscribe, e-mail: phplib-unsubscribe <email protected> For additional commands, e-mail: phplib-help <email protected>
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