Re: [phplib] Problem?? implode - Variable From: Jesse Swensen (swensenj <email protected>)
Date: 04/19/01

Not sure of this construction or what you are doing with it?
> $string1 = echo $string;

is this just a simple assignment? > $string1 = $string; 

-- 
Jesse Swensen
swensenj <email protected>

> From: GWBAG <email protected>
> Date: Thu, 19 Apr 2001 09:06:57 EDT
> To: phplib <email protected>
> Subject: [phplib] Problem?? implode - Variable
> 
> Hi, 
> 
> somebody knows where's  the problem, I get a parse error on line " if (trim
> ......."
> Thanks! Ralf
> 
> 
> $ObjTyp = array("'Einfamilienhaus'", "'Bauernhaus'");
> $string = implode(",", $ObjTyp);
> $string1 = echo $string;
> if (trim($ObjArt)=="Wohn") $ObjArt = '$string1';
> 
> $result=MYSQL_QUERY( "SELECT * FROM $tabelle where (ObjArt IN '$ObjArt') &&
> ..........
> 
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