RE: [phplib] I don't find the problem - From: Layne Weathers (layne <email protected>)
Date: 04/23/01

> i get a parse error problem on line ' ...where... like ......
snip
> $result=MYSQL_QUERY( "SELECT * FROM $tabelle where ObjArt
> like "'$ObjArt'" &&

You didn't make up your mind on whether you were going to use variable
substituion or string concatenation.

  "SELECT * FROM $tabelle where ObjArt like '$ObjArt'"
or
  'SELECT * FROM $tabelle where ObjArt like "'.$ObjArt.'"'

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