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php-db | 2001041

RE: [PHP-DB] array_diff usage From: Martin (chimbis <email protected>)
Date: 04/02/01

> I'm daft. I don't understand the PHP Manual.
>
> I have two arrays:
> Open[0] contains 1 2 3 4 5
> Closed[0] contains 1 2
>
> Now:
> $test = array_diff($Open, $Closed);

Given the setup you've described, I think you might actually want

        $test = array_diff($Open[0], $Closed[0]);

OK I'll try that.

> $lines = count($test);
> print $lines;
>
> Gives me: 1
> I thought it should be 3.

Seems appropriate, given the information you've provided. $Open and
$Closed each have only one element (0).

> While:
> for ($counter =0; $counter <= $lines -1; $counter++)
> {
> print $test[0];
> }
>
> gives me "5".

>This, on the other hand, makes me suspect that the arrays themselves
>don't actually contain what you think they do. How are you assigning
>the values you described at the top of your message?

I get them from a database by two select queries.
Then I do

$noOpened=mysql_num_rows($jobresult1);
        $noClosed=mysql_num_rows($jobresult2);
        $getlargest = strcmp($noOpened, $noClosed);

        switch ($getlargest) {
              case $getlargest > 0:
            $counttickets = $noOpened;
                while($sumOpen=mysql_fetch_row($jobresult1)) {
                 $Open = $sumOpen;
                 // DEBUG
                 print $Open[0] . "<br>";
                
               }
               while($sumClosed=mysql_fetch_row($jobresult2)) {
                 $Closed = $sumClosed;
                 // DEBUG
                 print "c" . $Closed[0] . "<br>";
               
               }

Which produces:
1
2
3
4
5
c1
c2

So the arrays are correctly set up (I think).

Martin S. 

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