php-db | 2001062
Date: 06/26/01
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I am having trouble with variable variables;
I want to create a form as follows :-
<?
$result = mysql_query("SELECT * FROM name_and_email");
$num = mysql_numrows("$result");
if ($num!="0") {
$i = 0;
PRINT "<FORM action='test.php'>";
WHILE ($i < $num) {
$name = mysql_result($result,$i,name);
$email = mysql_result($result,$i,email);
$id = mysql_result($result,$i,id);
PRINT "<INPUT type='text' name='name$id' value='$name'>";
PRINT "<INPUT type='text' name='email$id' value='$email'><BR>";
$i++;
}
PRINT "<INPUT type='submit'></FORM>";
}
?>
## THIS SHOULD SUBMIT SOMETHING LIKE THIS >>>>
test.php?name1=avalue&email1=avalueagain&name2=secondname&email2=secondemail
THE PROBLEM:
>From PHP with variable variables, how do I change $name1 and $email1 into -
## for all $name.$x values do this......
$sql = "UPDATE name_and_email SET name = '$name1', email = '$email1' WHERE
id = '$id'";
Many thanks if someone can help,
Morgan Tocker.
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- Next message: Hector M Banda: "[PHP-DB] How do I keep the values of objects when refreshing page?"
- Previous message: sang: "[PHP-DB] error ORA-12699"
- Next in thread: Taylor, Stewart: "RE: [PHP-DB] Variable Variables in PHP"
- Maybe reply: Taylor, Stewart: "RE: [PHP-DB] Variable Variables in PHP"
- Reply: Jason Stechschulte: "Re: [PHP-DB] Variable Variables in PHP"
- Maybe reply: Jonathan Hilgeman: "RE: [PHP-DB] Variable Variables in PHP"
- Maybe reply: Jonathan Hilgeman: "FW: [PHP-DB] Variable Variables in PHP"
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