php-db | 2002122
Date: 12/16/02
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I need to use PHP to duplicate the schema of a database. This seems like
it should be a simple task -- taking a 'template' db and cloning it with
a new name.
I've tried things like:
$filename = "myDB.sql";
$fd = fopen ($filename, "r");
$sql = fread ($fd, filesize ($filename));
fclose ($fd);
And
$lines = file($filename);
foreach ($lines as $line_num => $line) { $sql .= $line;
}
And
$sql .= "CREATE TABLE IP_Dept (";
$sql .= " IP_Addr int(10) unsigned NOT NULL default
'0',";
$sql .= " DeptID int(10) unsigned NOT NULL default
'0'";
$sql .= ");";
$sql .= "CREATE TABLE ResolveTable (";
$sql .= " IP_Addr int(10) unsigned NOT NULL default
'0',";
$sql .= " Name char(255) NOT NULL default '',";
$sql .= " Custom char(1) default NULL,";
$sql .= " Global char(1) default 'Y',";
$sql .= " OSVersion char(255) default NULL,";
$sql .= " RowID int(10) unsigned NOT NULL
auto_increment,";
$sql .= " Display enum('Yes','No') NOT NULL default
'Yes',";
$sql .= " PRIMARY KEY (RowID)";
$sql .= ");";
echo "<PRE>".$sql."</PRE><P>";
$result = mysql_query($sql,$linkI);
But ALL of them fail! Ugh!!! Can I not stack commands like that? Is
there some way to read in a .sql file via PHP? The problem is that my
web pages are on a web server and the db is on a mysql server which are
different machines, so calling a system() or other execute style
function won't work for me.
I figured, "Ah! Why don't I just make a template db on the server and
issue some SQL command to 'clone' that and rename it". You'd think that
was pretty straight forward, but I can't find any examples or commands
to do this seemingly trivial task. Ideas?
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- Reply: Rick Widmer: "Re: [PHP-DB] How can I use PHP to duplicate a mysql template database?"
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