php-general | 2000071

Re: [PHP] Troubled code (or my troubled brain) From: Reuben D Budiardja (reubendb <email protected>)
Date: 07/02/00

Try this:

if($id == $name)
{
statement
}
etc..

instead of
if($id == "$name")

I think your code evaluate if the content of the variable $id equal string
"$name" which is always false.

Reuben D. B

On Sun, 2 Jul 2000, Tyler Longren wrote:

>
> Hello List,
>
> I'm having problems with some code of mine. I don't know why it doesn't
> work. Here's the section that's troubled:
>
> if ($id == "$name") {
> echo "$count";
> }
> else {
> echo "0";
> }
>
> No matter what, this is always 0.
>
> I think that I have something wrong somewhere else in my code however and
> I don't know where it's at. So here's the rest of it (don't make fun of
> the dirtiness):
>
> <?
> echo "<Center><u><b>PHP Code</u></b></center><Br>";
> $connection = mysql_connect("host", "user", "pass") or die ("Unable to
> connect to server.");
> $db = mysql_select_db("cr0n", $connection) or die ("Unable to find
> requested database.");
> $result = mysql_query ("SELECT * FROM user_code WHERE language LIKE
> 'php'");
> $numrows = mysql_num_rows($result);
> while($row = mysql_fetch_array($result)) {
> $description = $row["description"];
> $email = $row["email"];
> $type = $row["type"];
> $id = $row["id"];
> $language = $row["language"];
> $author = $row["name"];
> $date = $row["date"];
> $result2 = mysql_query("SELECT * FROM counter WHERE name = '$id''");
> while($row2 = mysql_fetch_array($result2)) {
> $count = $row2["count"];
> $name = $row2["name"];
> }
> echo "<table width=75% align=center bgcolor=#000000 cellpadding=0
> cellspacing=0><tr><td bgcolor=#000000><table width=100% border=0
> cellspacing=1 cellpadding=1 height=0%>
> <tr>
> <td height=15 bgcolor=#000000 colspan=2><A
> href=\"viewcode.php?id=$id\"><font size=-1 color=#FFFFFF face=Arial,
> Helvetica, sans-serif>$description</font></a></td>
> </tr>
> <tr>
> <td bgcolor=#4A5A63 valign=top width=50% height=23>Author: <a
> href=\"mailto:$email\"><font size=-1 color=#000000 face=Arial, Helvetica,
> sans-serif>$author</font></a></td>
> <td bgcolor=#4A5A63 valign=top width=50% height=23>Date: $date</td>
> </tr>
> <tr>
> <td bgcolor=#4A5A63 valign=top width=50% height=24>Category: $type</td>
> <td bgcolor=#4A5A63 valign=top width=50% height=24>Views: ";
>
> //here's the troubled section
> if ($id == "$name") {
> echo "$count";
> }
> else {
> echo "0";
> }
> echo "</td></tr></table></td></tr></table><Br>";
>
> }
> if ($numrows == "0") {
> echo "<center><font color=#000000 size=2 face=Arial, Helvetica,
> sans-serif>No PHP code has been submitted yet!</font></center>";
> }
>
> mysql_free_result($result);
> ?>
>
> If anybody has any idead, please let me know, this is really bothering me.
>
> Regards,
> Tyler
>
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