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php-general | 2001062

Re: [PHP] PHP & ImageMagick From: Richard Lynch (ceo <email protected>)
Date: 06/29/01

> In PHP I try to run a shell command with the following source code:
>
> $fotonaam = 'convert -font arial -pointsize 20 -gravity center -fill
> white -draw "text 5,5 VERKOCHT" image.jpg image2.jpg';
> exec($fotonaam);
>
> PHP runs the program but the -draw "text 5,5 VERKOCHT" is not executed
> (there is no VERKOCHT in the image2.jpg). I tried everything but I can't
> solve the problem. Could somebody explain to me how it's possible that the
> program (convert) runs but there (seams to be) a problem with -draw "text
> 5,5 VERKOCHT". If I run the same command troughs telnet/ssh as root or
> nobody it works fine
>
> Is it something with the " and the combinative with the exec function (I
> also tried \")?
>
> Or is it because I run PHP in safe mode and the convert program tries to
run
> a external program what is not in the . path (you now, the basic safe mode
> restriction)?

Probably. Or maybe that program/lib just isn't in PHP's PATH. Try running
it as nobody, but set your $PATH to "" first.

Also, try using the optional parameters to http://php.net/exec so you can
get some feedback from the OS about what error is happening, if any. 

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