php-general | 2001092
Date: 09/30/01
- Next message: Richard Kurth: "[PHP] php_admin_flag safe_mode off"
- Previous message: andreas \( <email protected>\): "[PHP] session & class driving me nuts"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]
hi,
I am using ereg funtion to deal with data submmited by form
detail shown below:
I am using a form to submit some html code include image path code
In submitted php page, I want to replace image path code in html code
(submitted by last page' form), unfortunately the image path code include
some php variable (eg "imag src ='$phpvaribe'"),I want to use ereg function
to replace image path code by the value I need. but when I use eregi_replace
fuction try to replace it . but browser show me parsing error . I don't know
how to use eregi_replace() when php varible in string which needed to be
replaced. Could someone help me. My error code show below:
MY ERROR CODE:
eregi_replace("^\"(.)*{$img1_name}\"$","$replacestring",$content)
remark:the $img1_name is the php variable in the string which needed to be
replaced
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe <email protected> For additional commands, e-mail: php-general-help <email protected> To contact the list administrators, e-mail: php-list-admin <email protected>
- Next message: Richard Kurth: "[PHP] php_admin_flag safe_mode off"
- Previous message: andreas \( <email protected>\): "[PHP] session & class driving me nuts"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ]

