php-general | 2003022
Date: 02/18/03
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Greetings all,
My database has one table with three fields i.e. ClientID, ClientName
and Distance .
I`m trying to get all the field data printed to a form but whenever I
try to add the "ClientID" and "Distance" fields to the code below it
bombs out with the following error :
Parse error: parse error in /home/data/ClientWebs/chrisplay/main.php on
line 27
Full code is below :
<?php
//Connect to DB
include("inc_ConnectDB.php") ;
//Make SQL Statement
$SqlGetClient = "Select * from Client" ;
$ResGetClient = mysql_query($SqlGetClient) ;
//If any errors then print `em out
if (!$ResGetClient)
{
echo("<P>Error performing query: " . mysql_error() . "</P>");
exit();
}
//While there are records to fetch.....
while ( $row = mysql_fetch_array($ResGetClient) )
{
// THIS IS LINE 27
//....print them out to page
echo $row['ClientID'].['ClientName'].['Distance']. '<hr>';
}
?>
Muchos grassy-arse for any assistance......
-- Chris Blake Office : (011) 782-0840 Cell : 083 985 0379 It is reported that somewhere in the world, every 15 seconds, a woman gives birth to a child. She must be found and stopped.-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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