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php-general | 2003022

Re: [PHP] $_SESSIONS and printing off.. From: Frank Keessen (fkeessen <email protected>)
Date: 02/18/03

Thanks,

But then another question;

 if (isset($_SESSION['username']) && !empty($_SESSION['username'])) {
> echo 'Welcome '.$_SESSION['username'].', you are still logged in.';

I want also checked if the level of authentication = 2; for example
User Frank = level 1
User Rich = level 2

I've set $_SESSION['level'] to 2 but how can i check that with the above
line?

Thanks for your help,

Frank

----- Original Message -----
From: "Rich Gray" <rich <email protected>>
To: "Frank Keessen" <fkeessen <email protected>>; <php-general <email protected>>
Sent: Tuesday, February 18, 2003 11:53 AM
Subject: RE: [PHP] $_SESSIONS and printing off..

> Er... well I've seen a lot worse code than that but maybe you could use
...
>
> if (isset($_SESSION['username']) && !empty($_SESSION['username'])) {
> echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
> }
> else {
> header... etc etc
> }
>
> Rich
> > -----Original Message-----
> > From: Frank Keessen [mailto:fkeessen <email protected>]
> > Sent: 18 February 2003 09:00
> > To: php-general <email protected>
> > Subject: [PHP] $_SESSIONS and printing off..
> >
> >
> > Hi All,
> >
> > I'm a little bit confused and it's maybe a newbie question but
> > maybe you can help me out;
> >
> > A user is login in and after username password check it will
> > redirects to this page
> >
> > <?php
> > session_start();
> > if (isset($_SESSION['username'])){
> > $username = $_SESSION['username'];
> > echo 'Welcome, you are still loged in.';
> > echo $username;
> > }
> > else{
> > header ( "Location: login.htm" );
> > }
> > ?>
> >
> > Question is; is this the way to print of his username?
> >
> > $username = $_SESSION['username'];
> > Echo $username
> >
> > Or has anyone some alternatives..
> >
> > This is working o.k. but in my opinion it's a little bit quick and
dirty?
> >
> > Thanks for the comments and suggestions!
> >
> > Frank
>
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