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php-general | 2003022

Re: [PHP] $_SESSIONS and printing off.. From: Frank Keessen (fkeessen <email protected>)
Date: 02/18/03

Uh, sorry for the bad explanation Rich.. Again;

<?php
session_start();
if (isset($_SESSION['username']) && !empty($_SESSION['username'])){
echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
echo $_SESSION['woonplaats'];
}
else{
header ( "Location: login.htm" );
}
?>

This is working fine. But i've set $_SESSION['level'] to value 2 (that's
done in the php file that calls this one). Now i want the above code to
check for the level and if is not equal to two than go to the else (back to
login.htm) statement..

better explained??? ;>

Thanks,

Frank

----- Original Message -----
From: "Rich Gray" <rich <email protected>>
To: "Frank Keessen" <fkeessen <email protected>>; <php-general <email protected>>
Sent: Tuesday, February 18, 2003 1:25 PM
Subject: RE: [PHP] $_SESSIONS and printing off..

> Um... how about...
>
> echo 'Welcome '.$_SESSION['username'].', you are still logged in and your
> authentication level is '.(isset($_SESSION['level']) ? $_SESSION['level']
:
> 'unknown');
>
> Or am I missing something here?
>
> Rich
>
> > -----Original Message-----
> > From: Frank Keessen [mailto:fkeessen <email protected>]
> > Sent: 18 February 2003 12:15
> > To: Rich Gray; php-general <email protected>
> > Subject: Re: [PHP] $_SESSIONS and printing off..
> >
> >
> > Thanks,
> >
> > But then another question;
> >
> > if (isset($_SESSION['username']) && !empty($_SESSION['username'])) {
> > > echo 'Welcome '.$_SESSION['username'].', you are still logged in.';
> >
> >
> > I want also checked if the level of authentication = 2; for example
> > User Frank = level 1
> > User Rich = level 2
> >
> > I've set $_SESSION['level'] to 2 but how can i check that with the above
> > line?
> >
> > Thanks for your help,
> >
> > Frank
>
>
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