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php-general | 2005051

[PHP] Function shall receive Pointer to Array From: Fred Rathke (comrat <email protected>)
Date: 05/04/05

Hello,

how can a function get a pointer to an array? This does not work. I use
PHP4.

$t = array("test" => "unchanged");
echo "<br>testarray unchanged:\"".$t['test']."\"";
changearray($t);
echo "<br>testarray hopefully changed:\"".$t['test']."\"";

function changearray(&$myarray) {
$myarray['test'] = "changed";
}

Before I tried it on my own I read this page:
http://de2.php.net/manual/en/language.references.whatdo.php

Be so nice to search for this string: "The second thing references do
is to pass variables by-reference. This is done by making a local
variable in a function and a variable in the calling scope reference
to the same content. Example:"

The following example I used. I only tried to do it with an array
instead of a variable.

What I need to read again to find my own mistake? I know some of php's
commands work with an internal copy of a content.

Thanks for your help and advice. 

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