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php-general | 2005051
Date: 05/09/05
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On 5/9/05, Martín Marqués <martin <email protected>> wrote:
> I have a text variable that contains "$" symbols, that when I pass it out PHP
> thinks that the "$" mean that a variable name comes right after.
>
> I tried escaping the "$" put with no luck.
>
> Is there something I can do?
$var = 'hi $there';
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