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php-general | 2005051

Re: [PHP] expand array into function arguments? From: tg-php <email protected>
Date: 05/11/05

There's probably some clever answer to this like "Just do myFunc($myList) and it'll automatically parse out the arguments".. because PHP does clever things like that sometimes.

But if anything, you can do something like this:

$myList = array(1, "arg", 5);

myFunc($myList);

function myFunc($argarr) {
  list($arg1, $arg2, $arg3) = $argarr;
  #do something
}

You might try this and see if it works (again, PHP is clever like this sometimes):

$myList = array(1, "arg", 5);

myFunc($myList);

function myFunc($arg1, $arg2, $arg3) {
  list($arg1, $arg2, $arg3) = $argarr;
  #do something
}

Maybe it automatically splits the array for you.

-TG

= = = Original message = = =

You can do this in Python:

<code>
def myFunc(arg1, arg2, arg):
  #do something

myList = [1, "arg", 5]
myFunc(*myList) # calls myFunc(1, "arg", 2)
<code>

Can that be done in PHP, and if so, how?

Thanks for the help.

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