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php-general | 2005051

RE: [PHP] beginner needs help! From: Kim Madsen (km <email protected>)
Date: 05/13/05

> -----Original Message-----
> From: Jay Blanchard [mailto:jay.blanchard <email protected>]
> Sent: Thursday, May 12, 2005 9:37 PM

> > var $exportFile = "Export." . date("mdy") . ".txt";
>
> > I seem to be able to use the date function is I am not starting the
> > declaration with "var", but then my program is not working correctly.
> [/snip]
>
> You may have to assemble it beforehand sort of ...
>
> $exportFileName = "Export." . date("mdy") . ".txt";
> var $exportFile = $exportFileName;

May? You _have_ to. This behavior was introduced in PHP4 as the only non-PHP3 compatible OOP behavoir as far as I know. Nice spotted for a beginner Rochelle :-) I mean the "Iīm not allowed to use a function call while declaring with var".

Explanation:
PHP3 allowed one to use a function call while declaring a variable:

var $welcome_text = "Welcome " . get_username_from_db($loginname) . ". Today is " . date("l") . ", have a nice day";

As of PHP4 one _canīt_ use a function call when declaring a var, but _has_ to do as in Your example Jay:

var $welcome_text;
$welcome_text = "Welcome " . get_username_from_db($loginname) . ". Today is " . date("l") . ", have a nice day";

Pay attention to this though: You _not_ suppose to use var to declare a variable unless itīs inside a class. I never really tested that before, but outside a class this wonīt work:

<?
var $test = "hello";
echo $test; // returns nothing
?> 

--
Med venlig hilsen / best regards
ComX Networks A/S
Kim Madsen
Systemudvikler/Systemdeveloper

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