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php-windows | 2003112

RE: [PHP-WIN] Re: Regular Expression Question From: Gerardo Rojas (grojas <email protected>)
Date: 11/21/03

Okay, thanks for pointing that out.

How do we place multiple Replacements in the $replacement argument to preg_replace? I've added a double capture on my regular expression. If it is matched then I replace the the matched pattern by prefix a single character the the value of ${1} from the captured pattern. I have found out that I may need a second expression to capture all of the items in the file

<snip>

$aStr = array();
$aPat = array();
$aSum = array();

$aStr[] = "1. This is my first Qna";
$aStr[] = " 1. This is my first Qna";
$aStr[] = "11. This is my first Qna";

$aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/";
$aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/";
$aPat[] = "/(^\d{1,2}\.)|(^\s\d{1,2}\.)/";

****problem is here
$rep = "Q\${1}, ${2}";

$aSum = preg_replace($aPat, $rep, $aStr);
echo "<P>";

foreach( $aSum as $s )
{
        echo "string = $s <BR>";
} 

--
Gerardo S. Rojas
mailto: grojas <email protected>

-----Original Message-----
From: Andrei BEJENARU [mailto:abejenaru <email protected>]
Sent: Friday, November 21, 2003 9:50 AM
To: php-windows <email protected>
Subject: [PHP-WIN] Re: Regular Expression Question

Enclose a capturing group (\d) and the use prefix\${1} inside the
replacement.
Check out the PHP manual:

$string = "April 15, 2003";
$pattern = "/(\w+) (\d+), (\d+)/i";
$replacement = "\${1}1,\$3";

"Gerardo Rojas" <grojas <email protected>> wrote in message
news:F0EDCD6B96C14741A2F6B0BE6EB7D9CF6D703B <email protected>
I have a regular expression, that finds what i want.  The problem lies in
that I don't want to replace this pattern with another.  I want to prefix
the pattern with a character.  Any suggestions as to how I might accomplish
this?

regular expression = '/^\d\{1,2}\./'

--
Gerardo S. Rojas
mailto: grojas <email protected>

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