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php3-list | 199901

Re: [PHP3] Path From: Joey Smith (joey <email protected>)
Date: 01/26/99

Why not do:

<?

        $f = $DOCUMENT_ROOT . $PHP_SELF;

        echo "\$f = $f";
        echo "\n<BR>";

        $path = split("/", $f);

        $count = count($path);

        echo "\$count is $count";
        echo "\n<BR>";

        $count = $count - 1;

        $file = $path[$count];
        echo "The file name is $file";
?>

----- Original Message -----
From: John Coggeshall <someone <email protected>>
To: Jouni Ahto <jah <email protected>>
Cc: <mjnf <email protected>>; <php3 <email protected>>
Sent: Tuesday, January 26, 1999 9:52 AM
Subject: RE: [PHP3] Path

>> To my knowledge, there is no such command. If you just want to know which
>> program PHP would execute if you don't give a path (if you give it, then
>> you already know it...).
>
>What I am trying to figure out is if there are a few users
>
>/home/abc/al/
>/home/def/dan/
>/home/efg/eric/
>/home/hij/harry/
>
>and they are all running the same PHP Script I need to find out from which
>user's web page the script was ran. Is this possible? My goal is to write
>one mySQL-enabled script which will work for all of the users (with the PHP
>Script determining the right database depending on the user who ran it)
>
>John
>
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