PHP: func_get_args

Description

array func_get_args ( void )

Returns an array in which each element is a copy of the corresponding member of the current user-defined function's argument list. func_get_args() will generate a warning if called from outside of a function definition. This function cannot be used directly as a function parameter. Instead, its result may be assigned to a variable, which can then be passed to the function.

Note: This function returns a copy of the passed arguments only, and does not account for default (non-passed) arguments.

Note: Because this function depends on the current scope to determine parameter details, it cannot be used as a function parameter. If you must pass this value, assign the results to a variable, and pass the variable.


<?php

function foo() 

{

    $numargs = func_num_args();

    echo "Number of arguments: $numargs<br />\n";

    if ($numargs >= 2) {

        echo "Second argument is: " . func_get_arg(1) . "<br />\n";

    }

    $arg_list = func_get_args();

    for ($i = 0; $i < $numargs; $i++) {

        echo "Argument $i is: " . $arg_list[$i] . "<br />\n";

    }

} 



foo(1, 2, 3);

?>

func_get_args() may be used in conjunction with func_num_args() and func_get_arg() to allow user-defined functions to accept variable-length argument lists.