<?
/*
This is my first script in PHP!

Version 1.0

This function return a string containing date formatted for italian language:
You can see:
Name of the day - date (number) - name of the month - year (4 digits)
An example:
Gioved 22 Novembre 2001 (Tuesday 22 November 2001)

Hope its clear, my English it's not very good!

This script is free, enjoy it!

forlani73@libero.it
*/
function giorno() {
$giorno = date("l");
switch($giorno) {
	case "Sunday":
		$giorno = "Domenica "; //change in your language
		break;
	case "Monday":
		$giorno = "Luned "; //change in your language
		break;
	case "Tuesday":
		$giorno = "Marted "; //change in your language
		break;
	case "Wednesday":
		$giorno = "Mercoled "; //change in your language
		break;
	case "Thursday":
		$giorno = "Gioved "; //change in your language
		break;
	case "Friday":
		$giorno = "Venerd "; //change in your language
		break;
	case "Saturday":
		$giorno = "Sabato "; //change in your language
}
$mese = date("n");
switch($mese) {
	case "1":
		$mese = " Gennaio "; //change in your language
		break;
	case "2":
		$mese = " Febbraio "; //change in your language
		break;
	case "3":
		$mese = " Marzo "; //change in your language
		break;
	case "4":
		$mese = " Aprile "; //change in your language
		break;
	case "5":
		$mese = " Maggio "; //change in your language
		break;
	case "6":
		$mese = " Giugno "; //change in your language
		break;
	case "7":
		$mese = " Luglio "; //change in your language
		break;
	case "8":
		$mese = " Agosto "; //change in your language
		break;
	case "9":
		$mese = " Settembre "; //change in your language
		break;
	case "10":
		$mese = " Ottobre "; //change in your language
		break;
	case "11":
		$mese = " Novembre "; //change in your language
		break;
	case "12":
		$mese = " Dicembre "; //change in your language
}

// Change the order to get the exact string you want

$oggi = $giorno;		//name of the day
$oggi .= date("d");		//date (number)
$oggi .= $mese;			//name of the month
$oggi .= date("Y");		//year (4 digit)

return $oggi;
}
?>